My story

Lots of free agents and a lot of spills already. Free agency started at 3 PM and literally for twenty minutes I was constantly refreshing  woj  and  shams . Woj was winning with the reports tho xD    Anyway, here are all the reported signings and stuff. Damian Lillard=196M 4 yr super maximum contract extension Kevin Durant=Nets, 4 yr DeAndre Jordan=Nets Kyrie Irving=Nets, 4 yr Kemba Walker=Celtics, 4 yr Tobias Harris=Sixers, 4 yr Khris Middleton=Bucks, 5 yr, 178M(Largest contract for a 2nd-round pick in NBA history) Julius Randle=Knicks, 3 yr Brook Lopez=Bucks, 4 yr Jonas Valanciunas=Grizzlies, 3 yr Rudy Gay=Spurs, 2 yr George Hill=Bucks, 3 yr Gerald Green=Rockets, 1 yr Daniel House Jr.=Rockets, 3 yr Thomas Bryant=Wizards, 3 yr Derrick Rose=Pistons, 2 yr Terence Ross=Magic, 4 yr Al-Farouq Aminu=Magic, 3 yr Bojan Bogdanovic=Jazz, 4 yr Malcom Brogdon=Pacers, 4 year Rodney Hood=Blazers, 2 yr Terry Rozier=Hornets, 3 yr

I thought this writing problem turned out above average.  To find the vertex of the equation $y=-2x^2+bx+c$, we have to understand that the $x$ coordinate of the vertex can be found by taking the average of the x-intercepts and the $y$ coordinate can be found by letting $x=0$. Plugging it in leads to $y=c$, so we must find $c$ too. So to find the $x$ intercepts, we have to let $y=0$ leading to a quadratic. The sum of the roots of any quadratic is $-\frac{b}{a}$ from Vieta's formulas, and we can use this formula to help find $b$ Plugging in $b$ as $b$ and $a$ as $-2$, we get $\frac{-b}{-2}=\frac{b}{2}$ The sum of the roots can also be written as $(3+\sqrt5)+(3-\sqrt5)=6$ Since $6$ is the sum of the roots while $\frac{b}{2}$ can also be expressed as the sum of the roots, setting an equation will help us find $b$ $$\frac{b}{2}=6$$ $$b=12$$ So now our quadratic is $y=-2x^2+12x+c$ Now that found $b$ and $c$, the two vertexes can be found with ease. The $x$ coo

Bro today was HEATED xd Anyway Today at around 5 I rode my bike to Orloff and saw my friend and his brother. Let's call this friend uhhh BOBBY and my friend's brother uhhh BILLY Anyway, Billy is in like 4th or 5th grade while BOBBY is going to ninth. We gotta meet some more people too. So as soon as I got to the park, there was only one person and it was a tall Indian guy who looked like he was in highschool. Let's call him JOE Once I got there I challenged Joe to a 1v1 and I won 15-11. After that Bobby and Billy came along with this other guy who we will call JOEY. Joey looked like the same age as Joe. He was a little fatter and a little shorter. Then there's this other guy that came. Bobby, Billy, and that guy already came yesterday and we had a 2v2. We'll call this guy fudge i ran out of names BILLYBOB I didn't put John because he is NOT a John. Anyway, this guy looked like he was Caucasian and was the same age as B

Hi I am writing on a phone today so this won't be that good. I'm just here to put up my predictions for nba awards. U guys think I haven't been posting but I'm working on a big one. Anyway MVP James Harden ROY Luka doncic 6man Lou Williams DPOY Paul George Most improved Pascal soak am Coy Doc rivers

BANG I NEVER USE THE WORD LIT BUT THIS SONG IS LITERALLY LIT THIS SONG IS FIRE. 🔥 🔥 🔥 🔥 🔥 🔥 🔥 🔥 🔥 🔥 🔥 🔥 🔥 🔥 🔥 🔥 🔥 🔥 🔥 🔥 🔥 🔥 🔥 🔥 🔥 🔥 ok I'm good now.  dd Sunlight was released yesterday, and this song is just pure happiness. It has a great mood, tone, structure, and about everything. What a great summer song. TheFatRat chose to collaborate with Phaera, someone I know for his song Solitaire. I'd say Phaera is a synth pad person. Ok anyway here we go. The song starts off with an introduction of the melody, with a wind synth that is used in many of TheFatRat songs.  A similar synth can be found in  here(Xenogenesis) here(Windfall) here(Monody) here(Time Lapse) and probably more songs. In the beginning a stutter stick helps shift and bring the tone into a great setting. The first ten seconds is basically the teaser for the main melody,

From now on I am going to post the problem, solution with rendered latex, and bare solution. We begin by seeing that both $15^6$ and $7^6$ have even powers, meaning that difference of squares is applicable. From $a^2-b^2=(a+b)(a-b)$, we get $15^{3^{2}}-7^{3^{2}}=(15^3+7^3)(15^3-7^3)$ Another property in $a^3-b^3=(a-b)(a^2+ab+b^2)$ comes in handy to help further factorize the $(15^3-7^3)$ into $(15-7)(15^2+15\cdot 7+7^2)$ A similar property $a^3+b^3=(a + b)(a^2 - ab + b^2)$ can break apart $(15^3+7^3)$ into $(15+7)(15^2-15\cdot 7+7^2)$ Combining the two parts we end up with: $$(15-7)(15^2+15\cdot 7+7^2)(15+7)(15^2-15\cdot 7+7^2)$$ $$(8)(225+105+49)(22)(225-105+49)$$ $$(8)(379)(22)(169)$$ Since $379$ is prime and also the largest number in the factorization, the largest prime factor of $15^6-7^6$ is $\boxed{\boxed{379}}$ Lyric(s) of the Post: I can't wait to leave this town Cause lately I've been feeling down The cold nights just don't feel the same